F = m v^2/R
81.3 = m (2.92)^2 / 2.13
A girl sits on a tire that is attached to an overhanging
tree limb by a rope 2.13 m in length.
The girl’s father pushes her with a tangential
speed of 2.92 m/s. Besides the force opposing
the girl’s weight, the magnitude of the force
that maintains her circular motion is 81.3 N.
What is the girl’s mass?
Answer in units of kg.
2 answers
sksks
2 answers