Question
A 50kg girl sits at the top of a slide 6m long tilted at an angle of 30 degrees. if it takes her 3.3s to slide to the bottom and the coefficient of kinetic friction is 0.45, how fast will she be going at the bottom?
Answers
Henry
d = 0.5a*t^2 = 6 m.
0.5a*3.3^2 = 6
5.445a = 6
a = 1.102 m/s^2.
V^2 = Vo^2 + 2a*d = 0 + 2.204*6 = 13.22
V = 3.64 m/s.
0.5a*3.3^2 = 6
5.445a = 6
a = 1.102 m/s^2.
V^2 = Vo^2 + 2a*d = 0 + 2.204*6 = 13.22
V = 3.64 m/s.