Asked by zach
A load of 66 N attached to a spring hanging
vertically stretches the spring 8.3 cm. The
spring is now placed horizontally on a table and stretched 11 cm.
What force is required to stretch it by this amount?
Answer in units of N.
vertically stretches the spring 8.3 cm. The
spring is now placed horizontally on a table and stretched 11 cm.
What force is required to stretch it by this amount?
Answer in units of N.
Answers
Answered by
Henry
k = 66N/8.3cm = 7.95 N/cm.
F = 11cm * 7.95N/cm =
F = 11cm * 7.95N/cm =
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