Question
When a load of 1(10)^6 N is placed on a ship, the ship only sinks 2.5 cm into the ocean (sea water). Estimate the cross-sectional area of the ship at water level.
Answers
How amusing - you happened upon a Naval Architect.
increased volume of ship in the water = Area * .025 meters
mass of water displaced = density of seawater * that volume
density of seawater is about 1029 kg/m^3
so
mass of water displaced = 1029 * .025 * A
Buoyancy force due to that water = mass * 9.81 m/s^2 gravity
so
additional buoyant force up
= 9.81*1029 * .025 * A
so Archimedes says
1,000,000 = 9.81 * 1029 * .025 * A
increased volume of ship in the water = Area * .025 meters
mass of water displaced = density of seawater * that volume
density of seawater is about 1029 kg/m^3
so
mass of water displaced = 1029 * .025 * A
Buoyancy force due to that water = mass * 9.81 m/s^2 gravity
so
additional buoyant force up
= 9.81*1029 * .025 * A
so Archimedes says
1,000,000 = 9.81 * 1029 * .025 * A
Related Questions
How would I o about solving this:
When a load of 1000000 Newtons is placed on a battleship, the...
When a load of 0.89 106 N is placed on a battleship, the ship sinks only 1.9 cm in the water. Estima...
When a load of 0.97 106 N is placed on a battleship, the ship sinks only 3.0 cm in the water. Estima...
A ship has an area of cross sections as the water line of 2000m,by what depth does the ship sink in...