Asked by Myra
Suppose that after you are loaded into a FerrisWheal car, the wheel beguins turning at 3 revs/min.The wheal had a diameter of 20m and the bottom of the seat of the wheel is 2m above the ground. Express the hight of the seat above the ground as a function of time (t seconds), after it begins turning.
Answers
Answered by
drwls
The ferris wheel angle of the car from the lowest position is
A = 2 pi f t where f = 3/60 = 0.05 rev/second and t is the time it passes the lowest position
The height of the seat above the ground has a minimum value of 2 m.
At other times, the height h is
h = 2 + 20 (1 - cos 2 pi f t)
A = 2 pi f t where f = 3/60 = 0.05 rev/second and t is the time it passes the lowest position
The height of the seat above the ground has a minimum value of 2 m.
At other times, the height h is
h = 2 + 20 (1 - cos 2 pi f t)
Answered by
Reiny
Period = 20 sec
2pi/k = 20, k = pi/10
amplitude = 10
so how about:
height = 10sin pi/10(t-5) + 12
check:
t=0, height = 2
t=5, height = 12
t=10, height = 22
t=15 height = 12
t= 20 height = 2 , checks out.
2pi/k = 20, k = pi/10
amplitude = 10
so how about:
height = 10sin pi/10(t-5) + 12
check:
t=0, height = 2
t=5, height = 12
t=10, height = 22
t=15 height = 12
t= 20 height = 2 , checks out.
Answered by
drwls
I assumed the radius was 20, but it was the diameter. 20 in my equation should be 10.
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