As I see from the diagram, if the tree's height is h, and the distance to the point is x, then
(h-3)/x = tan30°40'
x = h cot65°10' + 3tan65°10'
Now just plug and chug.
from a point 3 m above the water surface, the angle of elevation of the top of a certain tree is 30°40', while the angle of depression of its image is 65°10'. Find the height of the tree and its distance from the point of observation.
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