Asked by choleng13
From a point 5m. above the water surface, the angle of elevation of the top of a certain tree is 40°10' while the angle of depression to the foot of the tree is 63°20'. Find the height of the tree and the distance from the point of observation.
-Complete Solution Please.
Thanks:)
-Complete Solution Please.
Thanks:)
Answers
Answered by
Henry
Tan63.33 = Y1/X = 5/X
X*Tan63.33 = 5
X = 5/Tan63.33 = 2.51 m = Distance from
the point of observation.
Tan40.17 = Y2/X = Y2/2.51
Y2 = 2.51*Tan40.17 = 2.12 m.
h = Y1+Y2 = 5 + 2.12 = 7.12 m.
X*Tan63.33 = 5
X = 5/Tan63.33 = 2.51 m = Distance from
the point of observation.
Tan40.17 = Y2/X = Y2/2.51
Y2 = 2.51*Tan40.17 = 2.12 m.
h = Y1+Y2 = 5 + 2.12 = 7.12 m.
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