2cos^2 theta/3-1

1-2sin^2(theta/2)=2cos^2(theta/2)-1

sin theta/2cos theta/2=1/2 sine theta show the identiy and work

Solve: 2cos^2 theta - 3cos theta+ 1= 0 interval [0, 2ð)

cos theta= .5 2cos theta= .5 how do you do this?

2cos^2 theta + 5 sin theta - 4 = 0

Xsin(theta)-Ysin(theta)=rootX^2+Y^2 andcos^2(theta)/a^2+sin^2(theta)/b^2 then find correct relation

Xsin(theta)-Ysin(theta)=sqrtX^2+Y^2 and cos^2(theta)/a^2+sin^2(theta)/b^2=1/X^2+Y^2 then find correc...

2cos^2(theta) + Sin(theta)=1 I know I have to use the quadratic formula but i'm having trouble a...

solve the equation (2cos theta +1)(tan theta minus 1)=0 for all values between 0 and 2pii.

Cos(theta)sin(theta)-2cos(theta)=0

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