Asked by Albino manyiel
given that equation 2logx +log2= log5+10.solve for x
Answers
Answered by
Reed
The last I knew, Kampala was the capital of Uganda, but I'll take your word for it that you are taking it as a School Subject.
http://en.wikipedia.org/wiki/Kampala
http://en.wikipedia.org/wiki/Kampala
Answered by
Reiny
2logx + log2 = log5 + 10
log x^2 + log2 = log5 + 10
log x^2 = log5 - log2 + 10
logx^2 = log (5/2) = 10
logx^2 = 10.39794..
x^2 = 10^10.39794..
x = 10^5.19897..
x = appr 158,114
I suspect a typo which would change the order of operation.
my answer works for the equation the way it was typed.
check:
LS = 2log 158114 + log2
= 10.39784... + .301029...
= 10.69897..
RS = log5 + 10
= .69897.. + 10
= 10.69897..
log x^2 + log2 = log5 + 10
log x^2 = log5 - log2 + 10
logx^2 = log (5/2) = 10
logx^2 = 10.39794..
x^2 = 10^10.39794..
x = 10^5.19897..
x = appr 158,114
I suspect a typo which would change the order of operation.
my answer works for the equation the way it was typed.
check:
LS = 2log 158114 + log2
= 10.39784... + .301029...
= 10.69897..
RS = log5 + 10
= .69897.. + 10
= 10.69897..
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.