Question
show that 2logx(a+b)= 2logx a+logx(1+ 2b/a + b^2/a^2)
Answers
Steve
2log(a+b) = log (a+b)^2 = log (a^2+2ab+b^2)
2log a + log(1 + 2b/a + b^2/a^2)
= log (a^2 (a^2+2ab+b^2)/a^2)
looks the same to me
2log a + log(1 + 2b/a + b^2/a^2)
= log (a^2 (a^2+2ab+b^2)/a^2)
looks the same to me