Asked by Ryan
                Write the equation of the parabola
1.Vertex(2,5) Focus(2,-3)
2.Directrix=x=3/4 Focus(5/4,-3)
For 1. i got(x-2)^2=32(y-5)^2
For 2. i got y=8x^2-20x-61/60
            
        1.Vertex(2,5) Focus(2,-3)
2.Directrix=x=3/4 Focus(5/4,-3)
For 1. i got(x-2)^2=32(y-5)^2
For 2. i got y=8x^2-20x-61/60
Answers
                    Answered by
            Henry
            
    1. V(2,5), F(2,-3).
1/4a = -3-5 = -8.
4a = -1/8.
a = -1/32.
Y = a(x-h)^2 + k.
Y = (-1/32)(x-2)^2 + 5, Vertex Form
    
1/4a = -3-5 = -8.
4a = -1/8.
a = -1/32.
Y = a(x-h)^2 + k.
Y = (-1/32)(x-2)^2 + 5, Vertex Form
                    Answered by
            Henry
            
    2. D(3/4,-3), V(h,-3), F(5/4,-3).
1/2a = 5/4-3/4 = 2/4 = 1/2.
2a = 2, a = 1.
1/4a = 1/(4*1) = 1/4.
h = 3/4 + 1/4a = 3/4 + 1/4 = 4/4 = 1.
X = a(y-k)^2 + h.
X = (y+3)^2 + 1, Vertex form.
X = y^2 + 6y + 10, Standard form.
    
1/2a = 5/4-3/4 = 2/4 = 1/2.
2a = 2, a = 1.
1/4a = 1/(4*1) = 1/4.
h = 3/4 + 1/4a = 3/4 + 1/4 = 4/4 = 1.
X = a(y-k)^2 + h.
X = (y+3)^2 + 1, Vertex form.
X = y^2 + 6y + 10, Standard form.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.