parabola with vertex at (2,1) ... y = a(x-2)^2 + 1
axis the line y-1=0 ... oops, a horizontal parabola ... x = a(y-1)^2 + 2
passes through (5,0)
a(0-1)^2 + 2 = 5
a = 3
So, we are left with
x = 3(y-1)^2 + 2
Write the equation of the parabola with vertex at (2,1), axis the line y-1=0 and passes through (5,0).
1 answer