Ask a New Question

Question

Write the equation of the parabola with vertex at (2,1), axis the line y-1=0 and passes through (5,0).
5 years ago

Answers

oobleck
parabola with vertex at (2,1) ... y = a(x-2)^2 + 1

axis the line y-1=0 ... oops, a horizontal parabola ... x = a(y-1)^2 + 2

passes through (5,0)
a(0-1)^2 + 2 = 5
a = 3
So, we are left with
x = 3(y-1)^2 + 2
5 years ago

Related Questions

write the equation of the parabola y=ax^2+bx+c that passes through the points(0,3), (1,4), and (2,3) Write the equation of a parabola, in standard form, that goes through these points: (0, 3)... Write the equation of the parabola that has vertex (2.5, 2.75) and passes through the point (1, 5). 5. Write an equation of a parabola with a vertex at the origin and a directrix at v = 5 (1 point)... Write the equation of the parabola that passes through the points (−3,−4) , (−4,0) , and (2,6) .(... Write the equation of the parabola with a focus at (10,−3) and a directrix of x=2 . It will be he... Write the equation of the parabola that passes through the points ( − 3 , − 4 ) , ( − 4... Write the equation of the parabola with a focus at ( 10 , − 3 ) and a directrix of x =...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use