Asked by Lana
A car is traveling at 65 km/hr. The brakes are applied and the car stops in 3 seconds. What is the car's acceleration?
Answers
Answered by
Kevin
Well I'm not sure if you need it in MKS system or not but here is the conversion
66km/hr*1hr/60min*1min/60sec*1000m/1km
=18.06m/s or .01806km/s
Since the car is stopping its final velocity =0
Use the equation Vf=Vi+a*t
(Where vf is final velocity vi is initial velocity a is acceleration and t is time)
Rearrange equation to solve for a becomes
(Vf-Vi)/t=a
Vf=0 so
-Vi/t=a
-18.06m/s/3 sec=
-6.02m/s^2 where the negative sign is showing a deceleration ( or the direction of the acceleration, which is opposite of the motion of the car)
Hope this helps!
66km/hr*1hr/60min*1min/60sec*1000m/1km
=18.06m/s or .01806km/s
Since the car is stopping its final velocity =0
Use the equation Vf=Vi+a*t
(Where vf is final velocity vi is initial velocity a is acceleration and t is time)
Rearrange equation to solve for a becomes
(Vf-Vi)/t=a
Vf=0 so
-Vi/t=a
-18.06m/s/3 sec=
-6.02m/s^2 where the negative sign is showing a deceleration ( or the direction of the acceleration, which is opposite of the motion of the car)
Hope this helps!
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