Question
at 25 celcius, how many dissociated OH ions are there in 8.0x10^-1 L of aqueous solution with pH 4.73?
Answers
DrBob222
H2O ==> H^+ + OH^-
Kw = (H^+)(OH^-)
pH = 4.73 = -log(H^+) and I get approx 2E-5 but that's just a close estimate for (H^+). That makes (OH^-) = estimated 5E-10M
# mols OH^- = M x L = ? and each mols has 6.02E23 ions.
Kw = (H^+)(OH^-)
pH = 4.73 = -log(H^+) and I get approx 2E-5 but that's just a close estimate for (H^+). That makes (OH^-) = estimated 5E-10M
# mols OH^- = M x L = ? and each mols has 6.02E23 ions.