Asked by Danny
Solve system by substitution or elimination x+4y=13
2x+3y=6
2x+3y=6
Answers
Answered by
Steve
substitution:
x = 13-4y, so
2x+3y = 2(13-4y)+3y = 6
26-8y+3y = 6
-5y = -20
y = 4
so, x=13-4y=13-4*4 = -3
Elimination:
Multiply the 1st equation by 2, and you get
2x+8y=26
2x+3y=6
Now subtract and you have
5y=20
and so on as above,
x = 13-4y, so
2x+3y = 2(13-4y)+3y = 6
26-8y+3y = 6
-5y = -20
y = 4
so, x=13-4y=13-4*4 = -3
Elimination:
Multiply the 1st equation by 2, and you get
2x+8y=26
2x+3y=6
Now subtract and you have
5y=20
and so on as above,