Asked by jose
solve using substitution
4x + 3y= -3
2x + y = -1
4x + 3y= -3
2x + y = -1
Answers
Answered by
Christiaan
When we look at the second equation, we can transfer the term 2x to the other side of the equality. We get that:
2x+y = -1
<=> y = -1-2x
when we replace the y in the first equation by the value we just calculated, we get that:
4x + 3y= -3
<=> 4x + 3(-1-2x)=-3
<=> 4x - 3 -6x = -3
<=> -2x=0
<=> x=0
So, we find that x=0. When we replace this value for x in the equation we earlier found for y, we get that:
y=-1-(2*0)=-1
So, we find that x=0 and y=-1
2x+y = -1
<=> y = -1-2x
when we replace the y in the first equation by the value we just calculated, we get that:
4x + 3y= -3
<=> 4x + 3(-1-2x)=-3
<=> 4x - 3 -6x = -3
<=> -2x=0
<=> x=0
So, we find that x=0. When we replace this value for x in the equation we earlier found for y, we get that:
y=-1-(2*0)=-1
So, we find that x=0 and y=-1
Answered by
jose
thanxz
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