Asked by Sara

Find the inverse of the function
f(X)= 2x^2 - 3
Answered by Reiny
y = 2x^2 - 3
inverse:
x = 2y^2 - 3
2y^2 = x+3
y^2 = (x+3)/2

y = ± √( (x+3)/2 )

btw, the inverse is not a function
Answered by Steve
since f is not single-valued, it has no inverse.

For x>=0,
f^-1(x) = √((x+3)/2)

There is also a branch for x <= 0
Answered by Steve
sorry. The branches split at x = -3, not x=0.
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