Asked by EB

An object has an initial velocity of 2.25 m/s at 57.2 degrees. An acceleration of 133.4 m/s/s at 59.5 degrees is applied. What was the final speed after the object has a displacement of 8.8 m at 33.5 degrees?
Answered by Henry
Vf^2 = Vo^2 + 2a*d.