Asked by EB
An object has an initial velocity of 3.87 m/s at 40.3 degrees. 8.35 seconds later it is moving at 41.1 m/s at an angle of 26.5 degrees. What acceleration caused this change in velocity? (Give your answer in terms of the +x-axis, in degrees)
Answers
Answered by
Henry
V = Vo + a*t = 41.1m/s[26.5o].
3.87[40.3o] + a*8.35 = 41.1[26.5].
2.95+2.50i + a*8.35 = 36.8 + 18.3i.
a*8.35 = 36.8 + 18.3i - 2.95 - 2.50i.
a*8.35 = 33.9 + 15.8i = 37.4m/s[25o].
a = 4.48m/s^2[25o], CCW from +X-axis.
3.87[40.3o] + a*8.35 = 41.1[26.5].
2.95+2.50i + a*8.35 = 36.8 + 18.3i.
a*8.35 = 36.8 + 18.3i - 2.95 - 2.50i.
a*8.35 = 33.9 + 15.8i = 37.4m/s[25o].
a = 4.48m/s^2[25o], CCW from +X-axis.
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