Asked by celina
What is minimum value of e^2x+ e^-2x
Thx
Thx
Answers
Answered by
Steve
recall that this is just 2 cosh(x).
d/dx (cosh x) = sinh(x)
sinh(x) = 0 at x=0
so, the minimum value is 1+1 = 2
(or 2cosh(0) = 2)
Or, if you insist on the hard way,
y' = 2e^2x - 2e^-2x
= 2e^-2x (e^4x - 1)
y'=0 at e^4x=1, or x=0.
d/dx (cosh x) = sinh(x)
sinh(x) = 0 at x=0
so, the minimum value is 1+1 = 2
(or 2cosh(0) = 2)
Or, if you insist on the hard way,
y' = 2e^2x - 2e^-2x
= 2e^-2x (e^4x - 1)
y'=0 at e^4x=1, or x=0.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.