this equation is writing as ax^2+bx+c
you need to find x. the equation for x is x=b/2a
plug it in b=24 a=4
x=24/2x4=24/8=3
if x = 3 plug it in to your equation
4(3)^2+24(3)+39
4x9+72+39
36+72+39=147
so the vertex is (3,147)
because a is 24 its positive meaning it opens up makeing the minimum value the vertex(3,147)
What is the minimum value of the function f(x)= 4x^2+24x+39
1 answer
1 answer