What is the minimum value of x for this inequality?
4x + 3( x - 1/5) ≥ 1/5( 2 + x )
How in the hell do I do this? Couldn't there be an infinite amount of numbers??
4x + 3( x - 1/5) ≥ 1/5( 2 + x )
How in the hell do I do this? Couldn't there be an infinite amount of numbers??
Answers
Answered by
Reiny
4x + 3( x - 1/5) ≥ 1/5( 2 + x )
Just simplify it
4x + 3x - 3/5 ≥ 2/5 + x/5
don't like those fractions? , multiply each term by 5
20x + 15x - 3 ≥ 2 + x
I am sure you can handle it from there, let me know what answer you get
Just simplify it
4x + 3x - 3/5 ≥ 2/5 + x/5
don't like those fractions? , multiply each term by 5
20x + 15x - 3 ≥ 2 + x
I am sure you can handle it from there, let me know what answer you get
Answered by
PicturesDon'tChangeThePeopleInsideOfThemDo
I don't understand, what do you mean?
Answered by
PicturesDon'tChangeThePeopleInsideOfThemDo
7x - 3/5 ≥ 2/5 + x/5
Answered by
Reiny
ok, let's go with your messy-looking equation
7x - 3/5 ≥ 2/5 + x/5
7x - x/5 ≥ 2/5 + 3/5
(35/5)x - (1/5)x ≥ 5/5
(34/5)x ≥ 1
now multiply each side by 5
34x ≥ 5
now divide each side by 34
x ≥ 5/34
starting from my simplified version of
20x + 15x - 3 ≥ 2 + x
20x + 15x - x ≥ 5
34x ≥ 5
x ≥ 5/34 , same result, less messy calculations
7x - 3/5 ≥ 2/5 + x/5
7x - x/5 ≥ 2/5 + 3/5
(35/5)x - (1/5)x ≥ 5/5
(34/5)x ≥ 1
now multiply each side by 5
34x ≥ 5
now divide each side by 34
x ≥ 5/34
starting from my simplified version of
20x + 15x - 3 ≥ 2 + x
20x + 15x - x ≥ 5
34x ≥ 5
x ≥ 5/34 , same result, less messy calculations
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.