Asked by Henry
Find the Absolute Maximum and Absolute Minimum of f on (0,3].
f(x)=(x^3-4x^2+7x)/x
Multiple choice question
I know the minimum is (2,3) but the maximum is either nothing or (0,7) but I can't tell which one
f(x)=(x^3-4x^2+7x)/x
Multiple choice question
I know the minimum is (2,3) but the maximum is either nothing or (0,7) but I can't tell which one
Answers
Answered by
Steve
on the given domain,
f(x) = x^2-4x+7
minimum is f(2)=3
limit as x->0 of f(x) = 7
f(3) = 4
So,
abs min = -9
abs max = 7
not strictly true, since f(0) is undefined, and there is no maximum number less than 7.
See the graph at
f(x) = x^2-4x+7
minimum is f(2)=3
limit as x->0 of f(x) = 7
f(3) = 4
So,
abs min = -9
abs max = 7
not strictly true, since f(0) is undefined, and there is no maximum number less than 7.
See the graph at
Answered by
Steve
so, I guess the real(!) answer is indeed that there is no absolute max value.
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