Question

Calculate the mass of Fe(OH)3 s) produced by mixing 50.0 mL of 0.153 M KOH (aq) and 25.0 mL of 0.255 M Fe(NO3)3 (aq), and the number of moles of the excess reactant remaining in solution.

I got 0.242 g Fe(OH)3 and 3.83 mmol Fe3+ remaining.

Answer 1

I agree with 3.83 mmols ferric but the problem asks for mols and not mmols.

I don't agree with 0.242 g Fe(OH)3 formed

Answer 2

for each of the following reactions 3.00 moles of each reactant is present initially. Determine the limiting reactant and calculate the moles of product in parentheses that would form

Fe2O3 +3H2=2Fe3H2O