Asked by Wilmor
calculate the mass of khp required to prepare 100.0 l of a 0.150 mol/l solution
Answers
Answered by
DrBob222
Is that 100 L?
How many moles do you need? That's mols = M x L = 0.150 x 100 = 15.0
Then grams = mols KHP x molar mass KHP = ?
How many moles do you need? That's mols = M x L = 0.150 x 100 = 15.0
Then grams = mols KHP x molar mass KHP = ?
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