Question
a stone is thrown vertically upward at a speed of 10 m/s from a cliff that is 95m high. How long will it take the stone to reach the bottom?
Answers
find t when h=0.
h(t) = 95+10t-4.9t^2
h(t) = 95+10t-4.9t^2
Related Questions
A stone is thrown vertically upward. On its way up it passes point A with speed, v and point B, 3 m...
A stone is thrown vertically upward. On its way up it passes point A with speed v, and point B,
7.8...
A stone is thrown vertically upward with a speed of 11.0 m/s from the edge of a cliff 80.0 m high. H...
A stone is thrown vertically upwards with a velocity 30 ms −1 . If the acceleration
due to gravity...
A stone is thrown vertically upward at a speed of 27.70 m/s at time t=0. A second stone is thrown up...
a stone is thrown vertically upward an initial velocity of 12m/s from the top of a building . it tak...
Stone is thrown vertically downward with an inital speed of 2.0m/s from height of 10m, determine tim...
a stone is thrown vertically upwards from the ground to reach a maximum height of 90m .how long will...
a stone is thrown vertically downwards with a speed of 10 m/s from a bridge. acceleration under grav...