Asked by pavatharani
a stone is thrown vertically upward with an initial velocity u from the top of tower, reaches the ground with a velocity 3u. what is the height of tower?
Answers
Answered by
bobpursley
final KE=initialPE-initial KE
1/2 m v^2=mgh-1/2 m u^2
1/2m(9u^2-u^2)=mgh
solve for h.
1/2 m v^2=mgh-1/2 m u^2
1/2m(9u^2-u^2)=mgh
solve for h.
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