Asked by Anonymous
A stone is thrown vertically upward with a speed of 22.0 m/s. How fast is it moving when it reaches a height of 12.0 m?
Answers
Answered by
bobpursley
vf^2=Vu^2+2ad
vf^2= 22^2-2*9.8*12
solve for Vf
vf^2= 22^2-2*9.8*12
solve for Vf
Answered by
Anonymous
248.8
Answered by
Anonymous
15.77
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