Question

Water emerges vertically from a hose at ground level and rises to a height of 3.2 m.

(a) At what speed does the water emerge from the nozzle?

(b) How long is a given drop in the air?

Answer 1

(1/2) m Vi^2 = m g h
so
Vi = sqrt(2 g h)

v = Vi - g t
0 = Vi - 9.81 t
solve for t, time to rise to 3.2 m
then time in air = 2 t

Answer 2

How do I solve it in another way and please give it in full