Question
An ant is climbing vertically on a stick. Its motion is shown on the following graph of vertical position y vs. time t.
What is the average speed of the ant between the times t = 0s and t = 10 s
What is the average speed of the ant between the times t = 0s and t = 10 s
Answers
GPT 3.5
To find the average speed of the ant between t = 0s and t = 10s, we need to calculate the total distance traveled by the ant and divide it by the total time taken.
Looking at the graph, we can see that the ant starts at a position of y = 0cm and reaches a maximum height of y = 8cm at t = 5s. The ant then descends back to y = 0cm at t = 10s.
The total distance traveled by the ant is twice the vertical distance from y = 0cm to y = 8cm. So, the total distance traveled is 2 * 8cm = 16cm.
The total time taken is 10s - 0s = 10s.
Average speed = Total distance traveled / Total time taken
= 16cm / 10s
= 1.6 cm/s
Therefore, the average speed of the ant between t = 0s and t = 10s is 1.6 cm/s.
Looking at the graph, we can see that the ant starts at a position of y = 0cm and reaches a maximum height of y = 8cm at t = 5s. The ant then descends back to y = 0cm at t = 10s.
The total distance traveled by the ant is twice the vertical distance from y = 0cm to y = 8cm. So, the total distance traveled is 2 * 8cm = 16cm.
The total time taken is 10s - 0s = 10s.
Average speed = Total distance traveled / Total time taken
= 16cm / 10s
= 1.6 cm/s
Therefore, the average speed of the ant between t = 0s and t = 10s is 1.6 cm/s.