Asked by Cali
A puck of mass 0.03 kg slides across rough ice, experiencing a frictional force of 0.2 N. If it was moving at 36 m/s when I hit the ice patch,
A) How long did it take to stop?
B) What was the length of the ice patch?
I know I have initial velocity, mass and final velocity of 0. How do I find time? Is it considered uniform motion?
A) How long did it take to stop?
B) What was the length of the ice patch?
I know I have initial velocity, mass and final velocity of 0. How do I find time? Is it considered uniform motion?
Answers
Answered by
Steve
Since F=ma, the 0.2N friction causes a deceleration of .2/.03 = 1.67 m/s^2
so, its speed and position are described by
v = 36 - 1.67t
s = 36t - 0.83 t^2
You can find t when v=0 (stopped) and use that value to find the stopping position.
Not uniform motion, but uniform acceleration.
so, its speed and position are described by
v = 36 - 1.67t
s = 36t - 0.83 t^2
You can find t when v=0 (stopped) and use that value to find the stopping position.
Not uniform motion, but uniform acceleration.
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