Asked by Sheetal
A 0.168kg hockey puck slides at 11.4m/s. what is the work needed to stop the puck?
Answers
Answered by
Elena
The work is equal to the change of kinetic energy
W=ΔK=K2-K1= 0-(mv^2)/2
W=0.168•(11.4)^2/2=10.9 J.
W=ΔK=K2-K1= 0-(mv^2)/2
W=0.168•(11.4)^2/2=10.9 J.
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