Asked by cat21
An ice hockey puck slides along the ice at 12 m/s. A hockey stick delivers an impulse of 4.0 kg*m/s causing the puck to move off in the opposite direction with the same speed. What is the mass of the puck?
I tried all sorts of ways to set this up and I just cant seem to get it, help?
I tried all sorts of ways to set this up and I just cant seem to get it, help?
Answers
Answered by
drwls
The momentum change = 2*M*12 m/s = 24 M m/s
where m is the puck mass in kg
That equals the impulse, 4.0 kg m/s
M = 4.0/24 kg = 1/6 kg
where m is the puck mass in kg
That equals the impulse, 4.0 kg m/s
M = 4.0/24 kg = 1/6 kg
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