Asked by jennifer
solve
6x^2 - 5x +1 = 0
is this correct?
6x^2 - 2x - 3x + 1=0
-2x(-3x+1) 1(-3x +1)
(2x-1)=0 (3x-1)=0
x=1/2 x=1/3
6x^2 - 5x +1 = 0
is this correct?
6x^2 - 2x - 3x + 1=0
-2x(-3x+1) 1(-3x +1)
(2x-1)=0 (3x-1)=0
x=1/2 x=1/3
Answers
Answered by
drwls
The final answer is correct but there is an intermediate step that is wrong. You should have written
(2x-1)(3x-1) = 0
as the factoring step.
You did break up the quadratic correctly into
-2x(3x-1) + (-3x+ 1)
which can be written
(-3x+1)(-2x+1) = (3x-1)(2x-1)
(2x-1)(3x-1) = 0
as the factoring step.
You did break up the quadratic correctly into
-2x(3x-1) + (-3x+ 1)
which can be written
(-3x+1)(-2x+1) = (3x-1)(2x-1)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.