The final answer is correct but there is an intermediate step that is wrong. You should have written
(2x-1)(3x-1) = 0
as the factoring step.
You did break up the quadratic correctly into
-2x(3x-1) + (-3x+ 1)
which can be written
(-3x+1)(-2x+1) = (3x-1)(2x-1)
solve
6x^2 - 5x +1 = 0
is this correct?
6x^2 - 2x - 3x + 1=0
-2x(-3x+1) 1(-3x +1)
(2x-1)=0 (3x-1)=0
x=1/2 x=1/3
1 answer
1 answer