Question

A ship leaves port at noon and has a bearing of S 25° W. The ship sails at 15 knots. How many nautical miles south and how many nautical miles west does the ship travel by 6:00 P.M.? (Round your answers to two decimal places.)

Miles South?
Miles West?
distance in the direction of the bearing = 6(15) or 90 n miles.
make your sketch to see:
sin 25° = x/90
x = 90sin25 = appr 38.04 n miles
cos25= y/90
y = 90cos25= 81.57 n miles

Related Questions

"A ship leaves port on a bearing of 34.0 degrees and travels 10.4 mi. The ship then turns due east a... Q1: Prove cos^2t+4cost+4/cost+2=2sect+1/sect Q2: A ship leaves port with a bearing of S 40 W... A ship leaves port at noon at heads due east at 20 nautical miles/hour (20 knots). At 2PM the ship c...