Asked by Julia
From what height would a car weighing 9990 N have to fall to gain the kinetic energy equivalent to what it would have when traveling 64.87 mi/hr?
Answers
Answered by
Henry
M*g = 9990 N., M = 9990/9.8 = 1019 kg.
V = 64.87 mi/h * 1600m/mi * 1h/3600s. =
28.83 m/s.
KE = 0.5M*V^2 = 0.5*1019*(28.83)^2 = 423,481 J.
PE = Mg*h = KE.
9990*h = 423,481.
h = ?
V = 64.87 mi/h * 1600m/mi * 1h/3600s. =
28.83 m/s.
KE = 0.5M*V^2 = 0.5*1019*(28.83)^2 = 423,481 J.
PE = Mg*h = KE.
9990*h = 423,481.
h = ?
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