Asked by ephraim
what would be the height of a water barometer if atmospheric pressure is 1.0*10^5 Pa and the density of water is 1.0*10^3 kg/m^3? (Hint. Use p= 10 hd)
Answers
Answered by
Damon
p = rho g h
10^5 = 10^3 * 9.81 * h
h = 10^2/9.81
You seem to be using 10, not 9.81 for g so
h = 100/10 = 10 meters
That is about 33 feet which divers figure is about one atmosphere gage.
10^5 = 10^3 * 9.81 * h
h = 10^2/9.81
You seem to be using 10, not 9.81 for g so
h = 100/10 = 10 meters
That is about 33 feet which divers figure is about one atmosphere gage.
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