Question

a body of mass m hung in a particular spring execute shm if period 1seconds What period would be obtained?
a,using a body of mass 4m?

Answer 1

v=e/t
v=4m/1sec
v=4m/s

Answer 2

frequency = constant * sqrt (k/m)
4 times m is 1/2 frequency or TWICE the period

Answer 3

F = m a
F = -k x
m a = - k x

if simple harmonic motion
x = A sin (2 pi t/T)
v = A (2 pi/T) cos (2 pi t/T)
a = -A(2 pi/T)^2 sin (2 pi t/T)
= -(2 pi/T)^2 x
so
m (-2pi/T)^2 x= -k x

(T/2 pi)^2 = m/k
T = 2 pi sqrt(m/k)