Asked by Chris
Calculate the volume, in milliliters, of a 0.290 M LiOH solution that will completely neutralize each of the following:
a. 40.0 mL of a 0.130 M H3PO4 solution
b. 24.5 mL of a 0.535 M H2SO4 solution
a. 40.0 mL of a 0.130 M H3PO4 solution
b. 24.5 mL of a 0.535 M H2SO4 solution
Answers
Answered by
bobpursley
I will do one.
a) Normalityacid*volumeacid=Normalitybase*Vb
.130*3*40=.290*1*Vb
solve for volume base (LiOH)
note, Normality of an acid=Molarity*H+eqivalents
H+ equivalents of H3PO3 is 3
H+ equivalents of H2SO4 is 2
a) Normalityacid*volumeacid=Normalitybase*Vb
.130*3*40=.290*1*Vb
solve for volume base (LiOH)
note, Normality of an acid=Molarity*H+eqivalents
H+ equivalents of H3PO3 is 3
H+ equivalents of H2SO4 is 2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.