Question
Calculate the volume, in milliliters, of a 0.290 M LiOH solution that will completely neutralize each of the following:
a. 40.0 mL of a 0.130 M H3PO4 solution
b. 24.5 mL of a 0.535 M H2SO4 solution
a. 40.0 mL of a 0.130 M H3PO4 solution
b. 24.5 mL of a 0.535 M H2SO4 solution
Answers
bobpursley
I will do one.
a) Normalityacid*volumeacid=Normalitybase*Vb
.130*3*40=.290*1*Vb
solve for volume base (LiOH)
note, Normality of an acid=Molarity*H+eqivalents
H+ equivalents of H3PO3 is 3
H+ equivalents of H2SO4 is 2
a) Normalityacid*volumeacid=Normalitybase*Vb
.130*3*40=.290*1*Vb
solve for volume base (LiOH)
note, Normality of an acid=Molarity*H+eqivalents
H+ equivalents of H3PO3 is 3
H+ equivalents of H2SO4 is 2
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