Asked by bruge
How to calculate the volume of rotating object formed by the area between curve y=x^2 and y=3x which is rotating through :
a. x axis
b. y axis ; using skin tube methode
a. x axis
b. y axis ; using skin tube methode
Answers
Answered by
Steve
The curves intersect at (0,0) and (3,9)
So, rotating around the x-axis, using
discs:
v = ∫[0,3] π(R^2-r^2) dx
where R=3x and r=x^2
v = ∫[0,3] π((3x)^2-(x^2)^2) dx = 162π/5
shells (tubes):
v = ∫[0,3] 2πrh dy
where r=y and h=(√y)-(y/3)
v = ∫[0,9] 2πy(√y-y/3) dy = 162π/5
Now do the other part, interchanging the x and y interpretations.
So, rotating around the x-axis, using
discs:
v = ∫[0,3] π(R^2-r^2) dx
where R=3x and r=x^2
v = ∫[0,3] π((3x)^2-(x^2)^2) dx = 162π/5
shells (tubes):
v = ∫[0,3] 2πrh dy
where r=y and h=(√y)-(y/3)
v = ∫[0,9] 2πy(√y-y/3) dy = 162π/5
Now do the other part, interchanging the x and y interpretations.
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