Asked by walter
An object is launched at a speed of 15 m/s. If it rises to a height of 2 m, at what angle was it launched?
Answers
Answered by
Henry
Vo = 15 m/s.
Yf^2 = Yo^2 + 2g*h.
Yf = 0.
g = -9.8 m/s^2.
h = 2 m.
Yo = ?.
sin A = Yo/Vo.
A = ?
Yf^2 = Yo^2 + 2g*h.
Yf = 0.
g = -9.8 m/s^2.
h = 2 m.
Yo = ?.
sin A = Yo/Vo.
A = ?
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