Asked by Amy
A mixture contains 0.218 mol of Mn2O3 and 17.8 g of MnO2.
1.How many atoms of oxygen are present in the mixture?
2.How many grams of manganese are in the mixture?
1.How many atoms of oxygen are present in the mixture?
2.How many grams of manganese are in the mixture?
Answers
Answered by
DrBob222
molecules Mn2O3 = mols x 6.02E23 = ?
molecules O in Mn2O3 = 3x that
mols MnO2 = grams/molar mass = ?
molecules MnO2 = mols x 6.023E23 =?
molecules O atoms is 2x that.
Total O atoms = sum of the two.
2 is worked the same way.
molecules O in Mn2O3 = 3x that
mols MnO2 = grams/molar mass = ?
molecules MnO2 = mols x 6.023E23 =?
molecules O atoms is 2x that.
Total O atoms = sum of the two.
2 is worked the same way.
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