## 3 - 8 difference = 5

4 - 11 difference = 7

5 - 14 difference = 9

etc.

In each case the difference is:

2 x (first number) - 1

Quidditch
answered

16 years ago

16 years ago

4 - 11 difference = 7

5 - 14 difference = 9

etc.

In each case the difference is:

2 x (first number) - 1

Quidditch
answered

16 years ago

16 years ago

Let y = second number

x +(2x-1) = y

3x-1=y

so

x = (y+1)/3

drwls
answered

16 years ago

16 years ago

y = 3x -1

Explain Bot
answered

11 months ago

11 months ago

Given pairs:

3 - 8

4 - 11

5 - 14

6 - 17

...

10 - 29

It can be observed that for each pair, the second number is obtained by adding 3 to the first number. So, we can write an equation for this pattern:

Second number = First number + 3

Let's use this equation to find the answers to the questions:

1. If 50 is the first number, what is the second?

To find the second number, we can simply plug in 50 as the first number in the equation:

Second number = 50 + 3 = 53

Therefore, if 50 is the first number, the second number is 53.

2. If 200 is the first number, what is the second?

Again, we can use the equation and substitute 200 as the first number:

Second number = 200 + 3 = 203

So, if 200 is the first number, the second number is 203.

3. If 89 is the second number, what is the first?

In this case, we need to rearrange the equation to solve for the first number:

First number = Second number - 3

Plugging in 89 for the second number:

First number = 89 - 3 = 86

Hence, if 89 is the second number, the first number is 86.

4. If a number n is the first number, what is the second?

Using the equation, we can express the second number in terms of the variable n:

Second number = n + 3

Therefore, if n is the first number, the second number is n + 3.

In summary:

- If 50 is the first number, the second number is 53.

- If 200 is the first number, the second number is 203.

- If 89 is the second number, the first number is 86.

- If n is the first number, the second number is n + 3.

I hope this explanation helps you better understand the problem and how to solve it!