Nope. The region is symmetric, so you can just double the area on the interval [0,1]
See
https://www.wolframalpha.com/input/?i=2(integral%5B0..1%5D++(x-x%5E3)dx)
So, what did you do?
PS The above integral gives the total geometric area. If you want the net algebraic area, where regions below the x-axis are subtracted, then the result is zero.
another one i'm stumped by
What is the area between the curves x = y and y = x^3 from -1 to y = 1
i got 0.75 for this one, am i correct
2 answers
ohhh alright i think i understand, thank you