(3-4sin^2A)(1-3tan^2A) =(3-tan^2A)(4cos^A-3)

4tan^2u-1=tan^2u 3tan^2u=1 tan^2u=1/3 sq. root of (tan^2u)=sq. root of (1/3) tanu=sq. ro...

1. 4sin^2x=3tan^2x-1 2. 8cos^2x-4cos^4x=3 3. 3secx-cosx=2

Use the substitution x=3tan() to evaluate the indefinite integral 93dx/(x^2sprt(x^2+9))

((4sin(atan(4/3))-4sin(0)))-(-3cos(atan(4/3))-(-3cos(0)))+((-3cos(pi/2)-(-3cos(atan(4/3))))-(4sin(pi...

Prove that:(3-4sin^2A) (1-3tan^2A)=(3-tan^2A)(4cos^2A-3)

2+1/3tan(theta)=2 I know that tan=0 0,180 But i don't know how to figure it out. Please help.

tan^3(θ)=3tan(θ) solve for all solutions.. please provide steps so I can follow

Find dy/dx for y=3tan^-1(x/2). I know the answer is 6/x^2+4 but I'm stuck at y'=3(1/1+(x/2)^2)(1/...

3tan (x- pi/5)-sqrt(3) =0

(3-4sin^2thita)(1-3tan^A)=(3-tan^2A)(4cos^2A-3)

Asked by Shreya