According to the balanced equation below, how many moles of KBr will be made from 30.0 mL of 1.00 M HBr solution?

mols HBr = M x L = ?

mols KBr = mols HBr x (1 mol KBr/1 mol HBr) = ?

2.43

0.43

To determine the number of moles of KBr that will be produced, we need to use stoichiometry, which is based on the balanced equation.

The balanced equation is:
HBr(aq) + KOH(aq) → H2O(l) + KBr(aq)

From the equation, we can see that the stoichiometric ratio between HBr and KBr is 1:1. This means that for every 1 mole of HBr, we will get 1 mole of KBr.

First, we need to find the number of moles of HBr using the given information:
Volume of HBr solution = 30.0 mL = 30.0/1000 = 0.0300 L
Concentration of HBr solution = 1.00 M

Now we can calculate the number of moles of HBr:
moles of HBr = concentration × volume
moles of HBr = 1.00 M × 0.0300 L
moles of HBr = 0.0300 moles

Since the stoichiometric ratio between HBr and KBr is 1:1, the number of moles of KBr produced will also be 0.0300 moles.