Asked by Robin
Vehicle can travel 0-60mph in 7.6 sec. From a dead stop, what is the highest rate of speed vehicle can reach and decelerate to 10mph in 500 ft distance?
Answers
Answered by
Henry
60mi/h=60mi/3600s. * 1600m/mi = 26.7 m/s
10mi/h = 10/60 * 26.7 = 4.44 m/s.
500Ft. * 1m/3.3Ft = 152 m.
a = (Vf-Vo)/t = (26.7-0)/7.6 = 3.51 m/s.
Vf^2 = Vo^2 + 2a*d.
Vo^2 = Vf^2-2a*d = 4.44 - (-8.88)*152 =
1354.2
Vo = 36.8 m/s. = Max. initial velocity
for the given stopping distance.
10mi/h = 10/60 * 26.7 = 4.44 m/s.
500Ft. * 1m/3.3Ft = 152 m.
a = (Vf-Vo)/t = (26.7-0)/7.6 = 3.51 m/s.
Vf^2 = Vo^2 + 2a*d.
Vo^2 = Vf^2-2a*d = 4.44 - (-8.88)*152 =
1354.2
Vo = 36.8 m/s. = Max. initial velocity
for the given stopping distance.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.