Asked by Claire
6. A car traveling 64 km/hr (40 mi/h) brakes suddenly to avoid a dog crossing the road. It accelerated at a rate of -1350 mi/h2. What was its speed after 0.5 min?
Answers
Answered by
bobpursley
vf=vi+at
change that acceleration to m/s^2
-1350mi/hr^2 (1hr/3600sec)^2*1609m/mi
=-.167m/s^2 check that.
change that acceleration to m/s^2
-1350mi/hr^2 (1hr/3600sec)^2*1609m/mi
=-.167m/s^2 check that.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.