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Asked by anonymous

Parabolas; find Vertex, focus, directrix? 1) (y+1)^2 = -4(x-2)
10 years ago

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Answered by Steve
the parabola with directrix at x=p and vertex at (0,0), and focus at x = -p is

y^2 = 4px.

You have a parabola with
4p = -4, so p = -1
and it is shifted by (2,-1).

So,
vertex = (2,-1)
focus = (1,-1)
directrix: x = 3

See here for confirmation:

http://www.wolframalpha.com/input/?i=parabola+%28y%2B1%29^2+%3D+-4%28x-2%29
10 years ago
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