Asked by anonymous
Parabolas; find Vertex, focus, directrix? 1) (y+1)^2 = -4(x-2)
Answers
Answered by
Steve
the parabola with directrix at x=p and vertex at (0,0), and focus at x = -p is
y^2 = 4px.
You have a parabola with
4p = -4, so p = -1
and it is shifted by (2,-1).
So,
vertex = (2,-1)
focus = (1,-1)
directrix: x = 3
See here for confirmation:
http://www.wolframalpha.com/input/?i=parabola+%28y%2B1%29^2+%3D+-4%28x-2%29
y^2 = 4px.
You have a parabola with
4p = -4, so p = -1
and it is shifted by (2,-1).
So,
vertex = (2,-1)
focus = (1,-1)
directrix: x = 3
See here for confirmation:
http://www.wolframalpha.com/input/?i=parabola+%28y%2B1%29^2+%3D+-4%28x-2%29
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