Asked by Eric
                A rocket-powered hockey puck moves on a horizontal frictionless table. The figure below shows the graphs of vx and vy, the x- and y-components of the puck’s velocity. The puck starts at the origin.
The graph of the X-velocity is v=8t cm/s and the Y-velocity is V=30cm/s
Part A
In which direction is the puck moving at t = 2 s ? Give your answer as an angle from the x-axis.
Express your answer using two significant figures.
Part B
How far from the origin is the puck at 3 s ?
Express your answer to two significant figures and include the appropriate units.
            
            
        The graph of the X-velocity is v=8t cm/s and the Y-velocity is V=30cm/s
Part A
In which direction is the puck moving at t = 2 s ? Give your answer as an angle from the x-axis.
Express your answer using two significant figures.
Part B
How far from the origin is the puck at 3 s ?
Express your answer to two significant figures and include the appropriate units.
Answers
                    Answered by
            Henry
            
    A. X = 8*2 = 16 cm/s. Y = 30 cm/s.
Tan A = Y/X = 30/16 = 1.875.
A = 61.9o
B. X = 8*3 = 24 cm/s. Y = 30 cm/s.
Dx = 24cm/s * 3s = 72 cm.
Dy = 30cm/s * 3s = 90 cm.
D = sqrt(Dx^2 + Dy^2) =
    
Tan A = Y/X = 30/16 = 1.875.
A = 61.9o
B. X = 8*3 = 24 cm/s. Y = 30 cm/s.
Dx = 24cm/s * 3s = 72 cm.
Dy = 30cm/s * 3s = 90 cm.
D = sqrt(Dx^2 + Dy^2) =
                    Answered by
            bob
            
    115.256 cm
    
                    Answered by
            Zach
            
    B. X = (1/2)(a)(t)^2 = (1/2)(8)(3)^2 = 36 cm
Y = (v(0))(t) = (30)(3) = 90cm
D = sqrt(x^2+y^2) = sqrt(36^2+90^2) = sqrt(9396)
~ 97 cm
    
Y = (v(0))(t) = (30)(3) = 90cm
D = sqrt(x^2+y^2) = sqrt(36^2+90^2) = sqrt(9396)
~ 97 cm
                    Answered by
            john
            
    i dont kow
    
                    Answered by
            Kevin
            
    Herny is wrong
    
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